![]() ![]() Valid device, it is crucial that you keep it private. Then, register the debug token you logged in the previousĪfter you register the token, Firebase backend services will accept it as valid.īecause this token allows access to your Firebase resources without a ![]() Of the Firebase console, choose Manage debug tokens from your app's For example: D DebugAppCheckProvider: Enter this debug secret into the allow list in A localĭebug token will be logged when the SDK tries to send a request to theīackend. Launch the app and trigger a call to a Firebase backend service. Val firebaseAppCheck = FirebaseAppCheck.getInstance()ĭebugAppCheckProviderFactory.getInstance() Java FirebaseApp.initializeApp(/*context=*/ this) įirebaseAppCheck firebaseAppCheck = FirebaseAppCheck.getInstance() įirebaseAppCheck.installAppCheckProviderFactory(ĭebugAppCheckProviderFactory.getInstance()) Kotlin+KTX FirebaseApp.initializeApp(/*context=*/this) ![]()
0 Comments
Leave a Reply. |
AuthorWrite something about yourself. No need to be fancy, just an overview. ArchivesCategories |